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Ballpark homers   Message List  
Reply | Forward Message #108 of 700 |
Re: [Stratmat] Ballpark homers

Gary is correct. Eight diamonds (or # in the computer game) is the most any
power hitter can get. The other homeruns on a good power hitter's card will be
straight shots or HR/DO splits. Good homerun hitters who have poor batting
averages will have HR fly(B) the rest.

The BP homeruns are supposed to simulate that more homeruns can be hit in
Colorado than Florida. The issue, however, is the wide variance some ball parks
experience from year to year even when their dimensions do not change.

That is another topic for another day.


----- Original Message -----
From: Gary Kirchherr
To: stratmat@yahoogroups.com
Sent: Saturday, July 16, 2005 5:40 PM
Subject: Re: [Stratmat] Ballpark homers


At 6:34 PM +0000 7/16/05, Dr. John Eigenauer wrote:

>Can someone explain to me in detail how ballpark homers work. In particular:
>
>What is a: #flyball b
>
>Let is suppose that a roll results in #HOMERUN 1-8. Am I correct in assuming
that one rolls the twenty sided die and if it comes up between 1 and 8, then one
follows that with another roll based upon the ballpark lefty-righty homerun
factor (let us say, 1-10)?

I'm assuming that the pound sign you typed before "flyball" and "HOMERUN" is
supposed to be a diamond. :-)

To answer your question: If you are *not* using the ballpark effects or
weather effects, ignore the diamond completely, and follow the result as stated
on the card.

If you *are* playing with ballpark or weather effects, IGNORE THE RESULT ON
THE CARD COMPLETELY and instead consult the homerun result on the ballpark chart
or weather chart (depending on which chart you're using). For instance, if
you're using the ballpark-effects chart, you roll the 20-sided die and look
under the "ball park homeruns" column to see whether the batter hit a dinger or
a flyball B.

By the way, you do the same thing for ballpark singles. If you're using the
ballpark-effects chart and get a hitter's-card result with a solid black
triangle, ignore the result on the card, roll the 20-sided die and check the
ballpark-effects chart under "ball park singles" to see if the result is a
single or lineout.

Finally, if you're using ballpark or weather effects and get a batter's-card
result with a hollow triangle, follow the results in italics instead of the one
in normal script.

>Why do so many players have identical ballpark homer counts on their cards. I
have looked at about 20-25 power hitters and they all have 8 total dice points
of HOMERUN 1-8 (a seven counts for six points, a six for five points, etc.)?

Are you talking about batter's-card results preceded by a diamond? The
diamonds simply ensures that some of their long balls will be homers in small
parks, and flyouts in others. The more power the batter has, then logically the
more diamonds he's going to have on his card. I hadn't actually compared the
diamond count on different power hitters, but perhaps eight is the most any
hitter can get.

-Gary K.

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E-mail: erie@...
Web site: http://www.kirchherr.com
ICQ No.: 4544564
Yahoo Messenger: indiansfaninpa


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Sat Jul 16, 2005 10:44 pm

johnrc33
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Message #108 of 700 |
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Can someone explain to me in detail how ballpark homers work. In particular: What is a: #flyball b Let is suppose that a roll results in #HOMERUN 1-8. Am I...
Dr. John Eigenauer
jeigenauer
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Jul 16, 2005
7:59 pm

... I'm assuming that the pound sign you typed before "flyball" and "HOMERUN" is supposed to be a diamond. :-) To answer your question: If you are *not* using...
Gary Kirchherr
indiansfaninpa
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Jul 16, 2005
9:40 pm

Gary is correct. Eight diamonds (or # in the computer game) is the most any power hitter can get. The other homeruns on a good power hitter's card will be...
jchristie1@...
johnrc33
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Jul 16, 2005
10:42 pm
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