I realize that this is a very old post that I'm replying to, however,
I do know the procedure. The tiebreaker always reverts to the first
step whenever one team is placed, so in your scenario divisional
record comes first. However, I believe that it was always intended
that all ties be first broken based upon head-to-head results, so in
that case KU would be first, followed by KSU, then Missouri.

It's possible that the wording of the rules has been changed since
you posted this. I've been part of a discussion on a Big 12 women's
message board about the ambiguities in the tiebreaker rules that had
not been clarified, although there had never been a case where it was
necessary.

Here's a link to the current Big 12 tiebreaker procedures:
http://www.big12sports.com/sports/m-baskbl/spec-rel/111605aab.html

Hope that clears things up.



--- In collegerpi@yahoogroups.com, "louisdj1976" <louisdj1976@...>
wrote:
>
> I've seen the tiebreaking procedures for the Big 12 tournament; and
> things make sense for the most part. However, there is something
> when 3+ teams from one division are tied that this page does not
> answer. I was wondering if anyone here knew how to handle it.
>
> Thought I could use this years' standings and what if, but cannot
> find something that will work nice. Thus, suppose 2 years from
now,
> Kansas, K-State and Mizzou finish 11-5 in the conference. Also
> suppose that KU wins in Columbia, while the other 5 games pairing
the
> trio is determined by the home team. Making up some division
records
> to finish we have the following
>
> TEAM Head-to-head Division
> Kansas 3-1 8-2
> Kansas State 2-2 5-5
> Mizzou 1-3 6-4.
>
> Clearly KU is the best of the 3 (see tiebreaker on Big 12 website
as
> to why). But who's 2nd? Do we use this round robin to break ALL
the
> ties? Or do we just seed KU and start all over for #2 (in which
case
> we'd have to use the 2nd tiebreaker, division record, and put
Mizzou
> in #2)?
>